filer/perf/simple-statistics/test/normal_distribution.test.js

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2014-12-17 07:54:29 +00:00
var test = require('tape');
var ss = require('../');
test('natural distribution and z-score', function(t) {
test('normal table is exposed in the API', function(t) {
t.equal(ss.standard_normal_table.length, 310);
t.equal(ss.standard_normal_table[0], 0.5);
t.end();
});
test('P(Z <= 0.4) is 0.6554', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
t.equal(ss.cumulative_std_normal_probability(0.4), 0.6554);
t.end();
});
test('P(Z <= -1.20) is 0.1151', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
t.equal(ss.cumulative_std_normal_probability(-1.20), 0.1151);
t.end();
});
test('P(X <= 82) when X ~ N (80, 25) is 0.6554', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
// A professor's exam scores are approximately distributed normally with mean 80 and standard deviation 5.
// What is the probability that a student scores an 82 or less?
t.equal(ss.cumulative_std_normal_probability(ss.z_score(82, 80, 5)), 0.6554);
t.end();
});
test('P(X >= 90) when X ~ N (80, 25) is 0.0228', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
// A professor's exam scores are approximately distributed normally with mean 80 and standard deviation 5.
// What is the probability that a student scores a 90 or more?
t.equal(+(1 - ss.cumulative_std_normal_probability(ss.z_score(90, 80, 5))).toPrecision(5), 0.0228);
t.end();
});
test('P(X <= 74) when X ~ N (80, 25) is 0.1151', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
// A professor's exam scores are approximately distributed normally with mean 80 and standard deviation 5.
// What is the probability that a student scores a 74 or less?
t.equal(ss.cumulative_std_normal_probability(ss.z_score(74, 80, 5)), 0.1151);
t.end();
});
test('P(78 <= X <= 88) when X ~ N (80, 25) is 0.6006', function(t) {
// Taken from the examples of use in http://en.wikipedia.org/wiki/Standard_normal_table
// A professor's exam scores are approximately distributed normally with mean 80 and standard deviation 5.
// What is the probability that a student scores between 78 and 88?
var prob88 = ss.cumulative_std_normal_probability(ss.z_score(88, 80, 5)),
prob78 = ss.cumulative_std_normal_probability(ss.z_score(78, 80, 5));
t.equal(+(prob88 - prob78).toPrecision(5), 0.6006);
t.end();
});
t.end();
});